hasil dari [tex](64) \frac{2}{3} = [/tex] bentuk sederhana [tex] \sqrt{6} \times \sqrt{3} = [/tex] bentuk sederhana [tex] \sqrt{32} - \sqrt{8} + \sqrt{1

[tex](64) \frac{2}{3} \\ ( {4}^{3} ) \frac{2}{3} = {4}^{2} = 16 \\ \\ \sqrt{6} \times \sqrt{3} = \sqrt{18} = 3 \sqrt{2} \\ \\ \sqrt{32} - \sqrt{8} + \sqrt{18} \\ 4 \sqrt{2} - 2 \sqrt{2} + 3 \sqrt{2} \\ 5 \sqrt{2} \\ \\ {9}^{6} \div {9}^{2} = {9}^{6 - 2} = {9}^{4} \\ \\ {8}^{4} - {8}^{2} = 4032[/tex]