jika f(x)=x^2+1 dan gof(x)=4x-3,maka g(x)=? Jawaban disertai cara ya..

gof(x)=4x-3
g(f(x))=4x-3
g(x^2+1)=4x-3
g(x)=4(x^2+1)-3
g(x)=4x^2+4-3
g(x)=4x^2+1

maaf Kalo slah..

mungkin gini...
[tex]f(x) = {x}^{2} + 1 \\ gof(x) = 4x - 3 \\ \\ {x}^{2} + 1 = a \\ {x}^{2} = a - 1 \\ x = \sqrt{a - 1} \\ \\ gof(x) = 4x - 3 \\ g(f(x)) = 4x - 3 \\ g( {x}^{2} + 1) = 4x - 3 \\ g(a) = 4( \sqrt{a - 1} ) - 3 \\ g(x) = 4( \sqrt{x - 1} ) - 3[/tex]