diketahui 3 log 2 = A dan 3 log 5 = B nilai 3 log 1,92 jika dinyatakan dalam a dan b adalah

dik.
³log2=A
³log5=B

dit. ³log1,92??
³log1,92
=³log(192/100)
=³log(48/25)
=³log(2⁴.3/5²)
=³log2⁴+³log3-³log5²
=4.³log2+³log3-2.³log5
=4A+1-2B
=4A-2B+1

³log 2=A
³log 5=B

³log 1,92
=³log 192/100
=³log 192 – ³log 100
=³log (64 x 3) – ³log (25 x 4)
=³log 64 + ³log 3 – ³log 25 + ³log 4
=³log 2⁶ + 1 – (³log 5² + ³log 2²)
=6 x ³log 2 + 1 – (2 x ³log 5 + 2 x ³log 2)
=6A + 1 – (2B + 2A)
=4A – 2B + 1
Semoga membantu............