Suatu larutan Ba(OH)2 memliki pH=12. Perhitungkan kemolaran larutan basa itu.

[tex]ph = 12 \\ ph = pkw - poh \\ poh = 14 - 12 = 2 \\ (oh - ) = mb.valensi \\ {1.10}^{ - 2} = mb.2 \\ mb = \frac{ {1.10}^{ - 2} }{2} = 0. {5.10}^{ - 2} [/tex]
semoga membantu ya kak..