A. 6√48 - 3√12 + 5√27= B. 7√50 - 2√18 - 2√32= Assalamualaikum Tolong bantuin yak

Mapel : Matematika
Bab : Menyederhakan Bentuk Akar

A]
6√48 - 3√12 + 5√27
= 6√16x3 - 3√4x3 + 5√9x3
= 24√3 - 6√3 + 15√3
= 18√3 + 15√3
= 33√3

B]
7√50 - 2√18 - 2√32
= 7√25x2 - 2√9x2 - 2√16x2
= 35√2 - 6√2 - 8√2
= 29√2 - 8√2
= 21√2

[tex]6 \sqrt{48} - 3 \sqrt{12} + 5 \sqrt{27} \\ = 6 \sqrt{16 \times 3} - 3 \sqrt{4 \times 3} + 5 \sqrt{9 \times 3} \\ = 6.4 \sqrt{3} - 3.2 \sqrt{3} + 5.3 \sqrt{3} \\ = 24 \sqrt{3} - 6 \sqrt{3} + 15 \sqrt{3} \\ = 33 \sqrt{3} [/tex]

[tex]7 \sqrt{50} - 2 \sqrt{18} - 2 \sqrt{32} \\ = 7 \sqrt{25 \times 2} - 2 \sqrt{9 \times 2} - 2 \sqrt{16 \times 2} \\ = 7.5 \sqrt{2} - 2.3 \sqrt{2} - 2.4 \sqrt{2} \\ = 35 \sqrt{2} - 6 \sqrt{2} - 8 \sqrt{2} \\ = 21 \sqrt{2} [/tex]