sebanyak 150 ml larutan ba(oh)2 0,02m ditambah 350 ml air. hitung ph larutan!
Kimia
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Pertanyaan
sebanyak 150 ml larutan ba(oh)2 0,02m ditambah 350 ml air. hitung ph larutan!
1 Jawaban
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1. Jawaban Divaegi
[OH-] = x. Mb
=2×2.10^-2
=4.10^-2
[OH-] camp = [OH-]1.V1+[OH-] 2.V2/V1+V2
= 4.10^-2×150+0/500
=6/500
= 0.012
pOH = -log [OH-]
=-log 12.10^-2
=2-log12
pH = 14-pOH
=14-(2-log12)
=12-log12
catatan : tanda (^) dibaca pangkat :)))