Diketahui f(x) =2x2+3x-1dan g(x) =x+2 jika h(x) = f(x).g(x), maka nilai h(-1)?

h×=(2x^2+3×-1)(×+2)
h×=2×^3+4×^2+3×^2+6×-×-2
hx= 2×^3+7×^2+5×-2
h (-1)= 2(-1)^3+7 (-1)^2+5 (-1)-2
h=2 (-1)+7 (1)-5-2
h=-2+7-5-2
h=-2