sebanyak n gram NaOH Mr 40 memiliki PH 12 jika dilarutkan dalam air volumenya 500 ml harga n adalah... gram

pH = 12
pOH = 14 - 12= 2
[tex]( {oh}^{ - } ) = {1.10}^{ - 2} [/tex]
[tex]( {oh}^{ - } ) = \frac{m}{mr} \times \frac{1000}{ml} \times valensi \: basa \\ {1.10}^{ - 2} = \frac{m}{40} \times \frac{1000}{500} \\ {2.10}^{4} \times {1.10}^{ - 2} = 1000m \\ 1000m = 2. {10}^{2} \\ m = \frac{ {2.10}^{2} }{1 {.10}^{3} } = 0.2[/tex]
semoga membantu