hitung pH larutan ch3cooh 0.1 M bila derajat ionisasinya 0.01

[tex] { \alpha }^{2} = \frac{ka}{ma} \\ ({1.10}^{ - 2} {)}^{2} \times {1.10}^{ - 1} = ka \\ {1.10}^{ - 5} = ka \\ \\ ( {h}^{ + } ) = \sqrt{ka \times ma} = \sqrt{ {1.10}^{ - 5} } \times {1.10}^{ - 1} = \sqrt{ {1.10}^{ - 6} } = {1.10}^{ - 3} \\ \\ ph = 3[/tex]
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