koordinat titik balik f(x)=x^2-6x+5 adalah a.(3,4) b.(-3,4) c.(3,-4) d.(-3,-4) e.(6,4)

jawab
fungsi kuadrat

f(x)= x^2 - 6x + 5
a = 1
b = - 6
c = 5

x = -b/2a = -(-6)/(2.1)
x = 6/2
x = 3
f(3) = 3² -  6.3. + 5 = 9 - 18 + 5
f(3) = -4
titk balik (x,y) = (3, -4)