persamaan garis yang sejajar 2y-x+5=0 dan melalui (2,2)

m = -a/b
Catatan :
m = gradien
-a = angka di depan variabel x
b = angka di depan variabel y

2y - x + 5 = 0
m = -(-1)/2 = 1/2

y - y1 = m (x - x1)
y - 2 = 1/2 (x - 2)
y - 2 = 1/2x - 1
y - 2 (2) = 1/2x - 1 (2)
2y - 4 = x - 2
x - 2 = 2y - 4
x - 2y = -2
atau
x - 2y + 2 = 0

2y-x+5 = 0 --> -x+2y+5 = 0
m = -a/b
m = 1/2
Sejajar, maka :
m1 = m2
m1 = 1/2 = m2

Melalui titik (2,2) maka
y-y1 = m(x-x1)
y-2 = 1/2 (x-2)
y-2 = 1/2x-1
y = 1/2x-1+2
y = 1/2x+1
---------------- ×2
2y = x+2
-x+2y-2 = 0
x-2y+2 = 0

Semoga membantu
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