mohon bantuannya kka

Mapel : Matematika
Materi : Persamaan Garis

Garis a melalui titik (-1,0) dan (0, 2)

[tex] \frac{y-y_1}{y_2-y_1}=\frac{x-x_1}{x_2-x_1} \\ \\ \frac{y-0}{2-0}=\frac{x-(-1)}{0-(-1)}\\ \\ \frac{y}{2}=\frac{x+1}{1} \\ \\ y=2(x+1) \\ \\ y=2x+2...........m=2 \\ \\ Kedua\ garis\ tegak\ lurus,\ maka\ m_1\times m_2=-1 \\ \\2\times m_2=-1 \to m_2=- \frac{1}{2}\\\\ \text{Garis b melalui titik (-1,0) dan m =} -\frac{1}{2}\\\\y-y_1=m(x-x_1)\\\\y-0=-\frac{1}{2}(x-(-1))\\ \\y=-\frac{1}{2}(x+1)\\\\y=-\frac{1}{2}x-\frac{1}{2}.........kedua\ ruas\ dikalikan\ 2\\\\2y=-x-1............Jawaban\ (B)[/tex]

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