Jk log 2 =x, log 3=y, dan log 5=z, nilai log 600 adlh...

[tex]log \hspace{1 mm} 600 = log \hspace{1 mm} (2^2 * 3 * 5 * 10) \\ = 2 \hspace{1 mm} log \hspace{1 mm} 2 + log \hspace{1 mm} 3 + + log \hspace{1 mm} 5 + log \hspace{1 mm} 100 \\ = 2x + y + z + 1[/tex]

log 2 = x
log 3 = y
log 5 = z
log 600 = log (2x2x2x3x5x5) = [tex]log2^3[/tex] + log 3 + [tex]log5^2[/tex] = (3 x log 2) + log 3 + (2 x log 5) = 3x + y + 2z