Diket : f(x)=cx+d f(2)=9 f(-3)=11 f(-6)=....
Matematika
DarmaWendly
Pertanyaan
Diket : f(x)=cx+d
f(2)=9
f(-3)=11
f(-6)=....
f(2)=9
f(-3)=11
f(-6)=....
1 Jawaban
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1. Jawaban AlfandyGulo
f(2) = 9
2c + d = 9
f(-3) = 11
-3c + d = 11
Maka
2c + d = 9
-3c + d = 11
..................... -
5c = -2
c = -(2/5)
Nilai d:
2c + d = 9
2(-2/5) + d = 9
-4/5 + d = 9
d = 9 + 4/5
d = 49/5
Maka
f(-6) = cx + d
f(-6) = (-2/5)(-6) + 49/5
f(-6) = 12/5 + 49/5
f(-6) = 61/5