Kerjakan no 2 saja dgn bnr thx

Kelas 8 Matematika
Bab Lingkaran

r = d/2
r = 20/2
r = 10 cm

a] ∠AOC = 180° - ∠BOC
∠AOC = 180° - 60°
∠AOC = 120°

Panjang busur AC
= 120°/360° . 2 . π . r
= 1/3 . 2 . 3,14 . 10
= 20,93 cm

b] Luas juring BOC
= 60°/360° . π . r . r
= 1/6 . 3,14 . 10 . 10
= 52,33 cm²

c] Luas ΔBOC
= 1/4 . r . r √3
= 1/4 . 10 . 10 . √3
= 25 √3 cm²

d] Luas tembereng
= luas juring - luas segitiga
= (52,33 - 25√3) cm²
= 52,33 - 43,3
= 9,03 cm²