hasil dari akar98 - akar32

[tex] = \sqrt{98} - \sqrt{32} \\ = \sqrt{49 \times 2} - \sqrt{16 \times 2} \\ = 7 \sqrt{2} - 4 \sqrt{2} \\ = 3 \sqrt{2} [/tex]

√98 - √32 = √7 × 14       -  √2 × 16
                =  √7 × 7 × 2  -  √2 x 4²
                =        7√2       -  4√2
                =  3√2