Matematika

Pertanyaan

2√8+√18+1/4√32+√200 bantuin ya lg ulangan nih wkwk

2 Jawaban


  • [tex]2 \sqrt{8} + \sqrt{18} + \frac{1}{4} \sqrt{32} + \sqrt{200} \\ = 2 \sqrt{4 \times 2} + \sqrt{9 \times 2} + \frac{1}{4} \sqrt{16 \times 2} + \sqrt{100 \times 2} \\ = 2.2 \sqrt{2} + 3 \sqrt{2} + \frac{1}{4} .4 \sqrt{2} + 10 \sqrt{2} \\ = 4 \sqrt{2} + 3 \sqrt{2} + \sqrt{2} + 10 \sqrt{2} \\ = 18 \sqrt{2} [/tex]
  • =  2√8 + √18 + 1/4√32 + √200
    =  2√4.√2 + √9.√2 + 1/4 √16.√2 + √100 .√2
    =  2×2 √2 + 3√2  +  1/4 × 4√2  + 10√2
    =  4√2 + 3√2 + √2 + 10√2
    =  18√2

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