Ph larutan asam sulfat 0,5 adalah

asam sulfat ->H2SO4 (asam kuat)
M = 0,5

ph =- log [ H+]

[ H+] = val.Asam x M
[ H+] = 2 x 0,5
[ H+] = 1

ph =- log [ H+]
ph = 0

semoga membantu....