Matematika

Pertanyaan

tolong bantu nomer 4 dan 5.
tolong bantu nomer 4 dan 5.

1 Jawaban

  • 4.
    Busur AB= sudut/360 *2*π*r
    Busur AB= 72/360 *2*3,14*20= 25,12 cm

    5.
    sudut1 : sudut2 : sudut3=3:5:10
    total= 3+5+10= 18

    sudut1= 3/18 *360= 360/6= 60°
    sudut2= 5/18 *360= 5*20= 100°
    sudut3= 10/18 *360= 10*20= 200°