Fungsi invers f(x) =4x + 2 f(x) =2x + 1/ x-3 g(x) =2 / 3x + 2

a) f(x) = 4x + 2
y = 4x + 2
4x = y - 2
x = (y - 2) / 4
f-¹(x) = (x - 2) / 4

b) f(x) = (2x + 1) / (x - 3)
y = (2x + 1) / (x - 3)
y(x - 3) = (2x + 1)
yx - 3y = 2x + 1
yx - 2x = 3y + 1
x(y - 2) = 3y + 1
x = (3y + 1) / (y - 2)
f-¹(x) = (3x + 1) / (x - 2)

g(x) =2 / 3x + 2
y = 2 / (3x + 2)
y(3x + 2) = 2
3xy + 2y = 2
3xy = 2 - 2y
x = (2 - 2y) / (3y)
g-¹(x) = (2 - 2x) / 3x