penyelesaian sistem persamaan linear 4x-3y=-4x dan 10x+9y=1 adalah

4x-3y=-4 (dikali -3) -12x + 9y = 12
10x+9y=1 (dikali 1) 10x + 9y = 1

-12x + 9y = 12
10x + 9y = 1
---------------------(dikurangi)
(-12-10)x = 12 - 1
-22x = 11
x = 11/-22 = -½

4x -3y = -4
3y = 4x + 4
3y = 4(-½) + 4 = -2 + 4 = 2
y = ⅔